-16=t^2+8t

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Solution for -16=t^2+8t equation: 



-16=t^2+8t

We move all terms to the left:

-16-(t^2+8t)=0

We get rid of parentheses

-t^2-8t-16=0

We add all the numbers together, and all the variables

-1t^2-8t-16=0

a = -1; b = -8; c = -16;
Δ = b2-4ac
Δ = -82-4·(-1)·(-16)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{8}{-2}=-4$

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